Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 445 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹45500 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
4. 4.A town has 14200 people. The population grows by 5% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹24000 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
8. 8.A town has 9900 people. The population grows by 15% every year. What will the population be after 1 year?
9. 9.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹26600 at 10% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹22800 at 5% per year for 2 years (in ₹)?
12. 12.What amount will ₹2400 grow to in 1 year at 5% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹24100 at 10% per year for 2 years (in ₹)?
14. 14.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
15. 15.What amount will ₹40000 grow to in 3 years at 20% per year compound interest (in ₹)?
16. 16.A scooter is worth ₹11200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
17. 17.What amount will ₹56800 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.A scooter is worth ₹42800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
19. 19.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.What amount will ₹22700 grow to in 2 years at 10% per year compound interest (in ₹)?
21. 21.A town has 13600 people. The population grows by 15% every year. What will the population be after 2 years?
22. 22.Find the compound interest on ₹16000 at 20% per year for 3 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹3600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
25. 25.A town has 20800 people. The population grows by 15% every year. What will the population be after 2 years?
26. 26.What amount will ₹23800 grow to in 1 year at 25% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹31800 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹58200 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.A town has 21200 people. The population grows by 5% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹40500 at 10% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
34. 34.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
35. 35.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
36. 36.A town has 32900 people. The population grows by 15% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
38. 38.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
39. 39.A scooter is worth ₹3900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹31900 at 10% per year for 2 years (in ₹)?

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