Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 450 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹57400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
3. 3.What amount will ₹15100 grow to in 1 year at 20% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹4900 at 20% per year for 2 years (in ₹)?
5. 5.What amount will ₹16000 grow to in 3 years at 10% per year compound interest (in ₹)?
6. 6.What amount will ₹40800 grow to in 2 years at 10% per year compound interest (in ₹)?
7. 7.What amount will ₹36000 grow to in 3 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹50500 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
10. 10.A town has 30100 people. The population grows by 12% every year. What will the population be after 1 year?
11. 11.What is the difference between the compound interest and the simple interest on ₹14900 at 10% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹16000 at 20% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹14300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹22800 at 15% per year for 2 years (in ₹)?
15. 15.What amount will ₹16800 grow to in 1 year at 5% per year compound interest (in ₹)?
16. 16.A town has 47900 people. The population grows by 5% every year. What will the population be after 1 year?
17. 17.A town has 37000 people. The population grows by 20% every year. What will the population be after 3 years?
18. 18.What is the difference between the compound interest and the simple interest on ₹3300 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹16800 grow to in 2 years at 20% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
24. 24.What amount will ₹24500 grow to in 1 year at 4% per year compound interest (in ₹)?
25. 25.A town has 47600 people. The population grows by 15% every year. What will the population be after 2 years?
26. 26.Find the compound interest on ₹51900 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.Find the compound interest on ₹18200 at 5% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
29. 29.A town has 56800 people. The population grows by 25% every year. What will the population be after 2 years?
30. 30.A town has 42700 people. The population grows by 12% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹28400 at 15% per year for 2 years, compounded every year (in ₹).
32. 32.What amount will ₹20300 grow to in 1 year at 8% per year compound interest (in ₹)?
33. 33.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
35. 35.A town has 42800 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹38400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
40. 40.Find the compound interest on ₹53200 at 8% per year for 1 year, compounded every year (in ₹).

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