Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 452 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹52000 at 15% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹24400 at 15% per year for 2 years, compounded every year (in ₹).
3. 3.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹4100 at 20% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹12800 at 25% per year for 1 year, compounded every year (in ₹).
12. 12.What amount will ₹27600 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹48800 at 5% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹18700 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹42400 at 15% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
23. 23.What amount will ₹23400 grow to in 1 year at 20% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹9200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
25. 25.What amount will ₹17600 grow to in 1 year at 4% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹47500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.A town has 45600 people. The population grows by 5% every year. What will the population be after 2 years?
28. 28.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹48200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
30. 30.A town has 13500 people. The population grows by 20% every year. What will the population be after 3 years?
31. 31.Find the compound interest on ₹7400 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 9200 people. The population grows by 20% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹26900 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹20000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
37. 37.A scooter is worth ₹50000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹18000 at 20% per year for 2 years (in ₹)?
39. 39.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
40. 40.What amount will ₹9200 grow to in 2 years at 10% per year compound interest (in ₹)?

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