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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 457 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  2. 2.What amount will ₹54900 grow to in 1 year at 10% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹10100 at 10% per year for 2 years, compounded every year (in ₹).
  4. 4.What amount will ₹18700 grow to in 1 year at 25% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹20500 at 20% per year for 3 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹27100 at 20% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹37200 at 25% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹41200 grow to in 2 years at 15% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  13. 13.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
  14. 14.What amount will ₹40000 grow to in 3 years at 25% per year compound interest (in ₹)?
  15. 15.What amount will ₹7700 grow to in 1 year at 8% per year compound interest (in ₹)?
  16. 16.What amount will ₹40800 grow to in 1 year at 8% per year compound interest (in ₹)?
  17. 17.A town has 49400 people. The population grows by 10% every year. What will the population be after 1 year?
  18. 18.What is the difference between the compound interest and the simple interest on ₹26800 at 15% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹20000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  20. 20.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹33600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  24. 24.A town has 45000 people. The population grows by 4% every year. What will the population be after 2 years?
  25. 25.A town has 9000 people. The population grows by 10% every year. What will the population be after 3 years?
  26. 26.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  27. 27.A town has 18000 people. The population grows by 4% every year. What will the population be after 1 year?
  28. 28.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹52000 grow to in 1 year at 25% per year compound interest (in ₹)?
  30. 30.What amount will ₹40800 grow to in 1 year at 10% per year compound interest (in ₹)?
  31. 31.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  32. 32.What amount will ₹45900 grow to in 1 year at 12% per year compound interest (in ₹)?
  33. 33.What amount will ₹8300 grow to in 1 year at 12% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  35. 35.A scooter is worth ₹39000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  36. 36.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹43800 at 20% per year for 1 year, compounded every year (in ₹).
  38. 38.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
  39. 39.What amount will ₹10000 grow to in 3 years at 10% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?

Answer key

  1. 144
  2. 60390
  3. 2121
  4. 23375
  5. 14924
  6. 648
  7. 1084
  8. 5724
  9. 20925
  10. 54487
  11. 20
  12. 2522
  13. 3125
  14. 78125
  15. 8316
  16. 44064
  17. 54340
  18. 603
  19. 18050
  20. 75867
  21. 18900
  22. 64
  23. 756
  24. 48672
  25. 11979
  26. 18522
  27. 18720
  28. 13725
  29. 65000
  30. 44880
  31. 12167
  32. 51408
  33. 9296
  34. 5780
  35. 34320
  36. 14580
  37. 8760
  38. 85169
  39. 13310
  40. 192

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