Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹51900 grow to in 1 year at 15% per year compound interest (in ₹)?
- 2.A town has 52500 people. The population grows by 4% every year. What will the population be after 2 years?
- 3.Find the compound interest on ₹4700 at 25% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹53700 at 12% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹6700 at 15% per year for 1 year, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹20900 at 20% per year for 2 years (in ₹)?
- 8.A town has 9700 people. The population grows by 10% every year. What will the population be after 1 year?
- 9.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
- 10.What amount will ₹39900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
- 12.What amount will ₹50400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 13.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹42000 at 20% per year for 1 year, compounded every year (in ₹).
- 15.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 16.A town has 51200 people. The population grows by 5% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹53100 at 20% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹11200 at 15% per year for 1 year, compounded every year (in ₹).
- 21.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 22.A scooter is worth ₹21000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 23.Find the compound interest on ₹27000 at 8% per year for 1 year, compounded every year (in ₹).
- 24.What amount will ₹35100 grow to in 1 year at 15% per year compound interest (in ₹)?
- 25.A scooter is worth ₹49600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 26.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 27.A town has 8000 people. The population grows by 10% every year. What will the population be after 2 years?
- 28.Find the compound interest on ₹20000 at 5% per year for 2 years, compounded every year (in ₹).
- 29.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 30.Find the compound interest on ₹30800 at 5% per year for 2 years, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹48000 at 15% per year for 2 years (in ₹)?
- 32.What amount will ₹24800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹26300 at 20% per year for 2 years, compounded every year (in ₹).
- 34.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹8100 at 10% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹17900. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 37.Find the compound interest on ₹25900 at 12% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹50700 at 10% per year for 2 years, compounded every year (in ₹).
- 39.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
Answer key
- 59685
- 56784
- 1175
- 6444
- 15264
- 1005
- 836
- 10670
- 120
- 57456
- 208
- 52920
- 12167
- 8400
- 27436
- 56448
- 792
- 828
- 2124
- 1680
- 40560
- 15309
- 2160
- 40365
- 44764
- 20412
- 9680
- 2050
- 648
- 3157
- 1080
- 38750
- 11572
- 16606
- 81
- 15752
- 3108
- 10647
- 37044
- 1632
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