Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 460 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹39000 at 10% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹56100 at 20% per year for 1 year, compounded every year (in ₹).
3. 3.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
4. 4.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
5. 5.What amount will ₹11900 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹18700 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 53600 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.A town has 25500 people. The population grows by 4% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹29000 at 25% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 57600 people. The population grows by 10% every year. What will the population be after 2 years?
11. 11.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹25000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
15. 15.Find the compound interest on ₹46300 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹49400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
19. 19.Find the compound interest on ₹17200 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹8400 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹45500 at 10% per year for 2 years (in ₹)?
25. 25.What amount will ₹23600 grow to in 2 years at 5% per year compound interest (in ₹)?
26. 26.What amount will ₹42500 grow to in 3 years at 20% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹42000 at 25% per year for 2 years (in ₹)?
29. 29.A town has 1600 people. The population grows by 25% every year. What will the population be after 3 years?
30. 30.A scooter is worth ₹11000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
32. 32.What amount will ₹22100 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.What amount will ₹23200 grow to in 2 years at 10% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹30800 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.A town has 27800 people. The population grows by 12% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹18600 at 20% per year for 2 years (in ₹)?
40. 40.A town has 40800 people. The population grows by 25% every year. What will the population be after 1 year?

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