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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 462 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹58000 grow to in 3 years at 10% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹56000 at 10% per year for 3 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹47200 at 15% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹18200 at 8% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  7. 7.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  8. 8.A town has 36800 people. The population grows by 15% every year. What will the population be after 1 year?
  9. 9.What is the difference between the compound interest and the simple interest on ₹42800 at 20% per year for 2 years (in ₹)?
  10. 10.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
  11. 11.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
  13. 13.What amount will ₹10000 grow to in 3 years at 10% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹19000 grow to in 2 years at 10% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹34700 at 8% per year for 1 year, compounded every year (in ₹).
  17. 17.A scooter is worth ₹42000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  18. 18.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
  19. 19.What amount will ₹44900 grow to in 2 years at 10% per year compound interest (in ₹)?
  20. 20.What amount will ₹56000 grow to in 2 years at 5% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹17200 at 20% per year for 1 year, compounded every year (in ₹).
  22. 22.A scooter is worth ₹4300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What amount will ₹8000 grow to in 2 years at 5% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹13700 at 12% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹17200 at 15% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹28200 grow to in 1 year at 5% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  29. 29.A scooter is worth ₹42500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  30. 30.Find the compound interest on ₹40100 at 12% per year for 1 year, compounded every year (in ₹).
  31. 31.A scooter is worth ₹41000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
  33. 33.What amount will ₹51400 grow to in 2 years at 20% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹36500 grow to in 1 year at 5% per year compound interest (in ₹)?
  36. 36.A town has 12800 people. The population grows by 8% every year. What will the population be after 1 year?
  37. 37.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  39. 39.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
  40. 40.What amount will ₹19600 grow to in 1 year at 5% per year compound interest (in ₹)?

Answer key

  1. 77198
  2. 7
  3. 18536
  4. 1062
  5. 1456
  6. 8827
  7. 20577
  8. 42320
  9. 1712
  10. 56784
  11. 34606
  12. 9984
  13. 13310
  14. 1248
  15. 22990
  16. 2776
  17. 35700
  18. 54900
  19. 54329
  20. 61740
  21. 3440
  22. 3225
  23. 8820
  24. 1644
  25. 2580
  26. 29610
  27. 4896
  28. 192
  29. 35972
  30. 4812
  31. 29889
  32. 58
  33. 74016
  34. 10592
  35. 38325
  36. 13824
  37. 14580
  38. 8
  39. 11664
  40. 20580

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