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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 466 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹21700 at 20% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹53300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  3. 3.A scooter is worth ₹4000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹49900 at 20% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹49700 at 10% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹51300 at 25% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  9. 9.What amount will ₹31600 grow to in 1 year at 25% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹18000 at 20% per year for 3 years, compounded every year (in ₹).
  12. 12.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹28800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  15. 15.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹9800 at 10% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹29200 at 10% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹48800 at 5% per year for 2 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹50100 at 25% per year for 1 year, compounded every year (in ₹).
  22. 22.A town has 15700 people. The population grows by 20% every year. What will the population be after 2 years?
  23. 23.Find the compound interest on ₹11100 at 10% per year for 1 year, compounded every year (in ₹).
  24. 24.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
  25. 25.What amount will ₹3200 grow to in 3 years at 25% per year compound interest (in ₹)?
  26. 26.What amount will ₹15200 grow to in 2 years at 10% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹22800 at 15% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹57800 at 20% per year for 2 years (in ₹)?
  29. 29.What amount will ₹33200 grow to in 1 year at 12% per year compound interest (in ₹)?
  30. 30.What amount will ₹26500 grow to in 2 years at 20% per year compound interest (in ₹)?
  31. 31.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
  32. 32.A scooter is worth ₹56400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  33. 33.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹3700 at 8% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
  36. 36.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹30300 at 20% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  39. 39.What amount will ₹26700 grow to in 1 year at 25% per year compound interest (in ₹)?
  40. 40.A town has 52800 people. The population grows by 10% every year. What will the population be after 2 years?

Answer key

  1. 868
  2. 50635
  3. 3680
  4. 1996
  5. 72
  6. 497
  7. 12825
  8. 1272
  9. 39500
  10. 2850
  11. 13104
  12. 10816
  13. 117
  14. 20808
  15. 612
  16. 98
  17. 1261
  18. 292
  19. 68
  20. 5002
  21. 12525
  22. 22608
  23. 1110
  24. 71875
  25. 6250
  26. 18392
  27. 7353
  28. 2312
  29. 37184
  30. 38160
  31. 35937
  32. 31725
  33. 9568
  34. 296
  35. 2250
  36. 27648
  37. 1212
  38. 10675
  39. 33375
  40. 63888

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