Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹21700 at 20% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹53300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 3.A scooter is worth ₹4000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹49900 at 20% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹49700 at 10% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹51300 at 25% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹31600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹18000 at 20% per year for 3 years, compounded every year (in ₹).
- 12.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹28800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 15.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹9800 at 10% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹29200 at 10% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹48800 at 5% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹50100 at 25% per year for 1 year, compounded every year (in ₹).
- 22.A town has 15700 people. The population grows by 20% every year. What will the population be after 2 years?
- 23.Find the compound interest on ₹11100 at 10% per year for 1 year, compounded every year (in ₹).
- 24.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
- 25.What amount will ₹3200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 26.What amount will ₹15200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹22800 at 15% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹57800 at 20% per year for 2 years (in ₹)?
- 29.What amount will ₹33200 grow to in 1 year at 12% per year compound interest (in ₹)?
- 30.What amount will ₹26500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 31.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 32.A scooter is worth ₹56400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 33.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹3700 at 8% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹30300 at 20% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
- 39.What amount will ₹26700 grow to in 1 year at 25% per year compound interest (in ₹)?
- 40.A town has 52800 people. The population grows by 10% every year. What will the population be after 2 years?
Answer key
- 868
- 50635
- 3680
- 1996
- 72
- 497
- 12825
- 1272
- 39500
- 2850
- 13104
- 10816
- 117
- 20808
- 612
- 98
- 1261
- 292
- 68
- 5002
- 12525
- 22608
- 1110
- 71875
- 6250
- 18392
- 7353
- 2312
- 37184
- 38160
- 35937
- 31725
- 9568
- 296
- 2250
- 27648
- 1212
- 10675
- 33375
- 63888
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