Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 468 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹18900 grow to in 1 year at 5% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹32800 at 5% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹10800 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹32800 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.A scooter is worth ₹37400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
8. 8.A town has 6100 people. The population grows by 15% every year. What will the population be after 1 year?
9. 9.A town has 5300 people. The population grows by 25% every year. What will the population be after 1 year?
10. 10.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
11. 11.Find the compound interest on ₹27200 at 25% per year for 3 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
13. 13.What amount will ₹54800 grow to in 2 years at 20% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹25800 at 20% per year for 2 years, compounded every year (in ₹).
15. 15.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
16. 16.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
18. 18.A town has 53200 people. The population grows by 5% every year. What will the population be after 2 years?
19. 19.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
20. 20.What amount will ₹48000 grow to in 2 years at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹41900 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.A scooter is worth ₹47200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
23. 23.Find the compound interest on ₹8000 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹54000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹36800 at 25% per year for 2 years (in ₹)?
28. 28.A scooter is worth ₹6000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
29. 29.Find the compound interest on ₹38000 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.A scooter is worth ₹57200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
31. 31.What amount will ₹58800 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹26400 at 10% per year for 1 year, compounded every year (in ₹).
33. 33.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
34. 34.What amount will ₹17700 grow to in 1 year at 25% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹36400 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
37. 37.A town has 7000 people. The population grows by 15% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹9200 at 10% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹4700 at 10% per year for 2 years (in ₹)?
40. 40.A town has 24800 people. The population grows by 20% every year. What will the population be after 1 year?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets