Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 471 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹38000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
3. 3.What amount will ₹14500 grow to in 3 years at 20% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.What amount will ₹53500 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹11100 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
8. 8.What amount will ₹5600 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.What amount will ₹43400 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
12. 12.A town has 24800 people. The population grows by 5% every year. What will the population be after 2 years?
13. 13.A scooter is worth ₹35600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹20500 at 20% per year for 1 year, compounded every year (in ₹).
15. 15.A town has 56400 people. The population grows by 5% every year. What will the population be after 2 years?
16. 16.What amount will ₹5100 grow to in 1 year at 10% per year compound interest (in ₹)?
17. 17.What amount will ₹25000 grow to in 3 years at 20% per year compound interest (in ₹)?
18. 18.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
19. 19.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹12000 grow to in 1 year at 25% per year compound interest (in ₹)?
23. 23.What amount will ₹55300 grow to in 2 years at 10% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
25. 25.What amount will ₹57700 grow to in 1 year at 4% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹24400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
28. 28.A scooter is worth ₹42500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
29. 29.A scooter is worth ₹20800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
30. 30.Find the compound interest on ₹36600 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹53400 at 10% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹30000 at 10% per year for 2 years (in ₹)?
33. 33.What amount will ₹45900 grow to in 2 years at 20% per year compound interest (in ₹)?
34. 34.A town has 40000 people. The population grows by 4% every year. What will the population be after 2 years?
35. 35.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹5600 at 25% per year for 2 years (in ₹)?
37. 37.A town has 39200 people. The population grows by 15% every year. What will the population be after 2 years?
38. 38.Find the compound interest on ₹12200 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹22100 grow to in 2 years at 20% per year compound interest (in ₹)?

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