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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 475 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  2. 2.What amount will ₹5200 grow to in 2 years at 25% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹50900 at 10% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹32400 at 25% per year for 1 year, compounded every year (in ₹).
  5. 5.A scooter is worth ₹9600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  6. 6.What amount will ₹34500 grow to in 1 year at 20% per year compound interest (in ₹)?
  7. 7.What amount will ₹9300 grow to in 1 year at 20% per year compound interest (in ₹)?
  8. 8.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  9. 9.What amount will ₹20800 grow to in 2 years at 5% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹56100 at 20% per year for 2 years (in ₹)?
  11. 11.What amount will ₹3600 grow to in 2 years at 25% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹12000 at 25% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹14200 grow to in 1 year at 15% per year compound interest (in ₹)?
  16. 16.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  17. 17.What amount will ₹57700 grow to in 1 year at 4% per year compound interest (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  19. 19.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹7700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  21. 21.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  22. 22.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
  23. 23.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹44800 at 25% per year for 3 years, compounded every year (in ₹).
  26. 26.What amount will ₹50800 grow to in 1 year at 25% per year compound interest (in ₹)?
  27. 27.A town has 31600 people. The population grows by 25% every year. What will the population be after 2 years?
  28. 28.A scooter is worth ₹34700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  29. 29.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹30800 at 20% per year for 1 year, compounded every year (in ₹).
  31. 31.A town has 12300 people. The population grows by 10% every year. What will the population be after 1 year?
  32. 32.Find the compound interest on ₹55100 at 12% per year for 1 year, compounded every year (in ₹).
  33. 33.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹4800 grow to in 2 years at 15% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹46700 at 15% per year for 1 year, compounded every year (in ₹).
  37. 37.A town has 43200 people. The population grows by 25% every year. What will the population be after 3 years?
  38. 38.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 368
  2. 8125
  3. 509
  4. 8100
  5. 4050
  6. 41400
  7. 11160
  8. 36501
  9. 22932
  10. 2244
  11. 5625
  12. 4965
  13. 112
  14. 6750
  15. 16330
  16. 18522
  17. 60008
  18. 192
  19. 18522
  20. 7315
  21. 28880
  22. 23328
  23. 12544
  24. 288
  25. 42700
  26. 63500
  27. 49375
  28. 31230
  29. 46875
  30. 6160
  31. 13530
  32. 6612
  33. 56448
  34. 8334
  35. 6348
  36. 7005
  37. 84375
  38. 3641
  39. 80
  40. 2522

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