← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 478 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹35200 at 5% per year for 2 years (in ₹)?
  4. 4.What amount will ₹24800 grow to in 1 year at 10% per year compound interest (in ₹)?
  5. 5.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
  6. 6.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
  7. 7.Find the compound interest on ₹7600 at 4% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹4000 at 25% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹5400 grow to in 1 year at 4% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹44000 at 5% per year for 2 years (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
  15. 15.A scooter is worth ₹5600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  16. 16.Find the compound interest on ₹59200 at 5% per year for 2 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹24800 at 10% per year for 1 year, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹25000 at 20% per year for 3 years, compounded every year (in ₹).
  19. 19.A scooter is worth ₹49500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  20. 20.A scooter is worth ₹37100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  24. 24.What amount will ₹17900 grow to in 1 year at 8% per year compound interest (in ₹)?
  25. 25.A town has 25600 people. The population grows by 15% every year. What will the population be after 2 years?
  26. 26.A town has 15200 people. The population grows by 5% every year. What will the population be after 2 years?
  27. 27.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
  28. 28.A scooter is worth ₹16800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  29. 29.A scooter is worth ₹56400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  31. 31.A town has 57600 people. The population grows by 15% every year. What will the population be after 2 years?
  32. 32.Find the compound interest on ₹33600 at 25% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹50000 at 20% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹59500 at 20% per year for 1 year, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹41900 at 20% per year for 2 years, compounded every year (in ₹).
  38. 38.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  39. 39.What amount will ₹37200 grow to in 1 year at 4% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹15000 at 15% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 540
  2. 12
  3. 88
  4. 27280
  5. 69984
  6. 67068
  7. 304
  8. 12501
  9. 2250
  10. 5616
  11. 29169
  12. 110
  13. 153
  14. 43740
  15. 5054
  16. 6068
  17. 2480
  18. 18200
  19. 25344
  20. 34132
  21. 36
  22. 136
  23. 29478
  24. 19332
  25. 33856
  26. 16758
  27. 225
  28. 16128
  29. 40749
  30. 336
  31. 76176
  32. 18900
  33. 81
  34. 288
  35. 2000
  36. 11900
  37. 18436
  38. 19044
  39. 38688
  40. 2250

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets