Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
- 2.What amount will ₹14000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹12200 at 5% per year for 1 year, compounded every year (in ₹).
- 4.What amount will ₹12700 grow to in 2 years at 10% per year compound interest (in ₹)?
- 5.A town has 18800 people. The population grows by 25% every year. What will the population be after 2 years?
- 6.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 7.A scooter is worth ₹25600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 8.A scooter is worth ₹53200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 9.What amount will ₹35600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 10.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 11.A town has 4800 people. The population grows by 5% every year. What will the population be after 2 years?
- 12.Find the compound interest on ₹22500 at 8% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹55200 at 15% per year for 2 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹38800 at 15% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹14300 at 20% per year for 2 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹60000 at 15% per year for 1 year, compounded every year (in ₹).
- 19.Find the compound interest on ₹9500 at 20% per year for 2 years, compounded every year (in ₹).
- 20.What amount will ₹37600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹23100 at 10% per year for 2 years (in ₹)?
- 22.What amount will ₹25200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 23.A town has 25700 people. The population grows by 10% every year. What will the population be after 2 years?
- 24.Find the compound interest on ₹20800 at 4% per year for 1 year, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹13300 at 10% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹48500 at 10% per year for 1 year, compounded every year (in ₹).
- 28.A town has 11200 people. The population grows by 20% every year. What will the population be after 2 years?
- 29.A scooter is worth ₹44600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 30.What amount will ₹58400 grow to in 1 year at 25% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹27600 at 25% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹9200 at 5% per year for 1 year, compounded every year (in ₹).
- 34.Find the compound interest on ₹28400 at 12% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹54600 at 20% per year for 2 years (in ₹)?
- 36.A town has 49300 people. The population grows by 25% every year. What will the population be after 1 year?
- 37.What amount will ₹37800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 38.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 39.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
- 40.What is the difference between the compound interest and the simple interest on ₹58400 at 5% per year for 2 years (in ₹)?
Answer key
- 25
- 15680
- 610
- 15367
- 29375
- 48
- 18496
- 29925
- 39249
- 24334
- 5292
- 3744
- 17802
- 90
- 873
- 6292
- 7632
- 9000
- 4180
- 47000
- 231
- 27783
- 31097
- 832
- 133
- 3783
- 4850
- 16128
- 42816
- 73000
- 900
- 1725
- 460
- 3408
- 2184
- 61625
- 41580
- 21600
- 42592
- 146
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