Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 484 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
3. 3.A scooter is worth ₹50000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹58800 at 5% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹14000 at 15% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹55000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
8. 8.What amount will ₹58500 grow to in 1 year at 20% per year compound interest (in ₹)?
9. 9.A town has 53000 people. The population grows by 20% every year. What will the population be after 2 years?
10. 10.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹33200 at 5% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹34400 at 12% per year for 1 year, compounded every year (in ₹).
13. 13.What amount will ₹34000 grow to in 2 years at 25% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹4200 at 20% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹57600 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹59600 at 15% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 10400 people. The population grows by 4% every year. What will the population be after 1 year?
18. 18.What amount will ₹2400 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.What amount will ₹38800 grow to in 1 year at 4% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹22400 at 15% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹9200 at 15% per year for 2 years (in ₹)?
24. 24.What amount will ₹58400 grow to in 2 years at 25% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹50000 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹9600 at 25% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
29. 29.A town has 5200 people. The population grows by 20% every year. What will the population be after 2 years?
30. 30.Find the compound interest on ₹28000 at 15% per year for 2 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹22700 at 20% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹13100 at 10% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹43200 grow to in 3 years at 25% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹3700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
35. 35.A town has 26400 people. The population grows by 5% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹29000 at 20% per year for 3 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹18800 at 20% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹7200 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).

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