Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 490 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹44400 at 25% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹50000 at 15% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹41100 at 20% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹10400 grow to in 2 years at 15% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹25200 at 15% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹26000 at 5% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹3700 at 20% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹33100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
11. 11.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
12. 12.A town has 30400 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
14. 14.A town has 37300 people. The population grows by 5% every year. What will the population be after 1 year?
15. 15.What is the difference between the compound interest and the simple interest on ₹37700 at 10% per year for 2 years (in ₹)?
16. 16.What amount will ₹43100 grow to in 1 year at 5% per year compound interest (in ₹)?
17. 17.A town has 26800 people. The population grows by 20% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹8000 at 10% per year for 3 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹47400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
20. 20.What amount will ₹31200 grow to in 1 year at 8% per year compound interest (in ₹)?
21. 21.What amount will ₹21000 grow to in 1 year at 8% per year compound interest (in ₹)?
22. 22.What amount will ₹3100 grow to in 2 years at 10% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
24. 24.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹59900 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 17400 people. The population grows by 25% every year. What will the population be after 1 year?
28. 28.Find the compound interest on ₹20300 at 4% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
30. 30.A town has 5000 people. The population grows by 20% every year. What will the population be after 3 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹5300 at 10% per year for 2 years (in ₹)?
32. 32.What amount will ₹28400 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.A town has 45600 people. The population grows by 5% every year. What will the population be after 2 years?
34. 34.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
36. 36.A town has 20200 people. The population grows by 12% every year. What will the population be after 1 year?
37. 37.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
38. 38.A town has 7200 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).

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