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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 494 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹2400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹13600 at 20% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹52900 at 10% per year for 2 years (in ₹)?
  6. 6.A town has 51200 people. The population grows by 25% every year. What will the population be after 3 years?
  7. 7.A scooter is worth ₹19000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  8. 8.A town has 59200 people. The population grows by 25% every year. What will the population be after 3 years?
  9. 9.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹42500 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹36200 at 12% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  14. 14.A town has 11900 people. The population grows by 15% every year. What will the population be after 1 year?
  15. 15.What is the difference between the compound interest and the simple interest on ₹3600 at 15% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
  17. 17.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
  18. 18.What is the difference between the compound interest and the simple interest on ₹34000 at 10% per year for 2 years (in ₹)?
  19. 19.What amount will ₹37500 grow to in 3 years at 20% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
  22. 22.What amount will ₹37000 grow to in 3 years at 20% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹21800 at 5% per year for 1 year, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹16500 at 4% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹37600 at 10% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹56000 at 25% per year for 2 years, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹24000 at 5% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹48600 at 20% per year for 2 years, compounded every year (in ₹).
  30. 30.A scooter is worth ₹15200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  31. 31.A town has 27000 people. The population grows by 10% every year. What will the population be after 3 years?
  32. 32.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  33. 33.A town has 45100 people. The population grows by 12% every year. What will the population be after 1 year?
  34. 34.Find the compound interest on ₹9300 at 8% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  37. 37.What amount will ₹34400 grow to in 1 year at 15% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹31600 at 5% per year for 2 years (in ₹)?
  39. 39.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?

Answer key

  1. 32
  2. 2166
  3. 1600
  4. 544
  5. 529
  6. 100000
  7. 15390
  8. 115625
  9. 27783
  10. 29
  11. 4250
  12. 4344
  13. 192
  14. 13685
  15. 81
  16. 42
  17. 24334
  18. 340
  19. 64800
  20. 625
  21. 832
  22. 63936
  23. 1090
  24. 660
  25. 2912
  26. 3760
  27. 31500
  28. 1200
  29. 21384
  30. 13376
  31. 35937
  32. 80
  33. 50512
  34. 744
  35. 10675
  36. 28
  37. 39560
  38. 79
  39. 56448
  40. 414

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