Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 499 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹10500 at 10% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹11900 at 12% per year for 1 year, compounded every year (in ₹).
3. 3.Find the compound interest on ₹44200 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
5. 5.A scooter is worth ₹49200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹8000 at 15% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹53700 grow to in 1 year at 10% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
12. 12.A scooter is worth ₹28800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
13. 13.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
14. 14.What amount will ₹58400 grow to in 1 year at 25% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹5000 at 4% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹39500 at 20% per year for 2 years (in ₹)?
17. 17.What amount will ₹25600 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹59500 at 4% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹32600 at 20% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹13600 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹54000 at 25% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
25. 25.A scooter is worth ₹37500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
26. 26.A town has 14000 people. The population grows by 10% every year. What will the population be after 3 years?
27. 27.A scooter is worth ₹26600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
28. 28.Find the compound interest on ₹3600 at 25% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹9000 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
31. 31.A scooter is worth ₹16000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
33. 33.What amount will ₹24300 grow to in 1 year at 10% per year compound interest (in ₹)?
34. 34.A town has 2700 people. The population grows by 10% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹57900 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹22000 grow to in 2 years at 5% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹17100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
38. 38.A town has 56200 people. The population grows by 4% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹27600 at 25% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹23000 at 10% per year for 3 years, compounded every year (in ₹).

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