Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 50 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 10400 people. The population grows by 5% every year. What will the population be after 2 years?
2. 2.Find the compound interest on ₹2400 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
4. 4.What amount will ₹31600 grow to in 1 year at 25% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 23500 people. The population grows by 20% every year. What will the population be after 3 years?
8. 8.What amount will ₹9200 grow to in 2 years at 10% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
10. 10.A town has 28900 people. The population grows by 8% every year. What will the population be after 1 year?
11. 11.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹17200 at 20% per year for 1 year, compounded every year (in ₹).
13. 13.A scooter is worth ₹34400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
14. 14.A town has 12000 people. The population grows by 25% every year. What will the population be after 2 years?
15. 15.Find the compound interest on ₹26200 at 8% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹50200 grow to in 2 years at 20% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹5400 at 10% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹4100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
19. 19.A town has 56000 people. The population grows by 10% every year. What will the population be after 3 years?
20. 20.A town has 9000 people. The population grows by 10% every year. What will the population be after 3 years?
21. 21.A scooter is worth ₹17500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
22. 22.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹54200 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹22400 grow to in 3 years at 25% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹32000 at 20% per year for 2 years (in ₹)?
27. 27.What amount will ₹50400 grow to in 1 year at 20% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹6600 at 20% per year for 2 years (in ₹)?
29. 29.A town has 22500 people. The population grows by 20% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹30000 at 10% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
32. 32.What amount will ₹30400 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹55400 at 10% per year for 2 years (in ₹)?
35. 35.What amount will ₹12400 grow to in 2 years at 25% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹17700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹21600 at 25% per year for 2 years (in ₹)?
39. 39.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets