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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 503 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹29000 at 8% per year for 1 year, compounded every year (in ₹).
  4. 4.A town has 51200 people. The population grows by 25% every year. What will the population be after 2 years?
  5. 5.What is the difference between the compound interest and the simple interest on ₹22400 at 15% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  7. 7.What amount will ₹40000 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.What amount will ₹55300 grow to in 2 years at 10% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹8400 at 15% per year for 2 years (in ₹)?
  10. 10.A town has 30800 people. The population grows by 15% every year. What will the population be after 1 year?
  11. 11.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
  12. 12.What amount will ₹13500 grow to in 3 years at 20% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹51300 at 20% per year for 2 years, compounded every year (in ₹).
  14. 14.What amount will ₹48900 grow to in 1 year at 10% per year compound interest (in ₹)?
  15. 15.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
  16. 16.Find the compound interest on ₹42000 at 5% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹14600 at 4% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹25800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  20. 20.A town has 18100 people. The population grows by 4% every year. What will the population be after 1 year?
  21. 21.What is the difference between the compound interest and the simple interest on ₹34200 at 20% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹6300 at 10% per year for 2 years, compounded every year (in ₹).
  23. 23.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹56400 at 15% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹48400 at 10% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹10400 at 10% per year for 2 years, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹7300 at 10% per year for 1 year, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
  31. 31.What is the difference between the compound interest and the simple interest on ₹55200 at 10% per year for 2 years (in ₹)?
  32. 32.What amount will ₹25500 grow to in 3 years at 20% per year compound interest (in ₹)?
  33. 33.What amount will ₹38400 grow to in 1 year at 20% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹26900 at 10% per year for 2 years, compounded every year (in ₹).
  35. 35.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  36. 36.What is the difference between the compound interest and the simple interest on ₹25800 at 10% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
  38. 38.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?

Answer key

  1. 26
  2. 414
  3. 2320
  4. 80000
  5. 504
  6. 72
  7. 46656
  8. 66913
  9. 189
  10. 35420
  11. 11448
  12. 23328
  13. 22572
  14. 53790
  15. 18816
  16. 4305
  17. 468
  18. 584
  19. 20898
  20. 18824
  21. 1368
  22. 1323
  23. 18522
  24. 112
  25. 1269
  26. 484
  27. 2184
  28. 1261
  29. 730
  30. 6360
  31. 552
  32. 44064
  33. 46080
  34. 5649
  35. 55566
  36. 258
  37. 47275
  38. 40768
  39. 92
  40. 96

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