Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 509 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹43800 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹35500 grow to in 1 year at 25% per year compound interest (in ₹)?
3. 3.A town has 4800 people. The population grows by 5% every year. What will the population be after 2 years?
4. 4.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
6. 6.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹45600 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹24900 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.What amount will ₹52300 grow to in 1 year at 10% per year compound interest (in ₹)?
12. 12.What amount will ₹56500 grow to in 3 years at 20% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹38400 at 20% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹49200 at 8% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 31100 people. The population grows by 12% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹55900 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹25600 at 15% per year for 2 years (in ₹)?
22. 22.What amount will ₹54000 grow to in 3 years at 10% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹53600 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹18000 at 10% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹44000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
26. 26.What amount will ₹13000 grow to in 2 years at 10% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹37500 at 10% per year for 2 years (in ₹)?
29. 29.What amount will ₹50200 grow to in 1 year at 5% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹41200 at 15% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹18700 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹23600 at 5% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹16900 at 15% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹51100 at 20% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
36. 36.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
37. 37.What is the difference between the compound interest and the simple interest on ₹37600 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹54400 at 25% per year for 1 year, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹55200 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹26000 at 10% per year for 3 years, compounded every year (in ₹).

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