Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 512 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
2. 2.A town has 9700 people. The population grows by 20% every year. What will the population be after 2 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹27600 at 15% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹38000 at 10% per year for 2 years (in ₹)?
6. 6.What amount will ₹51200 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.What amount will ₹35200 grow to in 2 years at 15% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹14800 at 10% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹7100 at 4% per year for 1 year, compounded every year (in ₹).
11. 11.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
12. 12.Find the compound interest on ₹10400 at 25% per year for 2 years, compounded every year (in ₹).
13. 13.A town has 17000 people. The population grows by 20% every year. What will the population be after 2 years?
14. 14.What amount will ₹41200 grow to in 2 years at 25% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹4100 at 20% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹7600 at 5% per year for 2 years (in ₹)?
17. 17.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
18. 18.What amount will ₹21700 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
21. 21.A scooter is worth ₹38300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
23. 23.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹3300 at 15% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹4400 at 25% per year for 2 years (in ₹)?
26. 26.A town has 50800 people. The population grows by 5% every year. What will the population be after 2 years?
27. 27.Find the compound interest on ₹11000 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
29. 29.What amount will ₹2500 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹48200 at 10% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹44400 at 20% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹36000 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹16100 at 20% per year for 2 years (in ₹)?
36. 36.A scooter is worth ₹36700. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹19600 at 25% per year for 2 years (in ₹)?
38. 38.A town has 54100 people. The population grows by 25% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹48300 at 20% per year for 2 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹16700 at 20% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets