Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 516 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹31200 at 15% per year for 2 years, compounded every year (in ₹).
2. 2.A scooter is worth ₹8600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹50400 at 20% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹33200 at 5% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹19000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
6. 6.What amount will ₹60000 grow to in 2 years at 15% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
8. 8.A town has 36000 people. The population grows by 20% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹4700 at 10% per year for 2 years (in ₹)?
10. 10.A town has 10700 people. The population grows by 12% every year. What will the population be after 1 year?
11. 11.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹18800 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
14. 14.What amount will ₹55800 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹24800 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹7700 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹5600 at 8% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹2200 at 15% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
21. 21.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹48800 at 15% per year for 2 years, compounded every year (in ₹).
23. 23.A scooter is worth ₹54400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
24. 24.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹26500 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹43600 at 15% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹9100 at 20% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹18000 at 25% per year for 2 years (in ₹)?
30. 30.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
31. 31.A town has 10000 people. The population grows by 5% every year. What will the population be after 2 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹58800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
35. 35.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹43600 at 15% per year for 2 years (in ₹)?
37. 37.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
38. 38.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹43200 at 25% per year for 2 years (in ₹)?

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