Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 4.A scooter is worth ₹4500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹19200 at 15% per year for 1 year, compounded every year (in ₹).
- 8.A town has 5800 people. The population grows by 10% every year. What will the population be after 2 years?
- 9.Find the compound interest on ₹25400 at 20% per year for 1 year, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹28800 at 25% per year for 2 years (in ₹)?
- 12.What amount will ₹43600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 13.Find the compound interest on ₹27200 at 25% per year for 2 years, compounded every year (in ₹).
- 14.A town has 52500 people. The population grows by 4% every year. What will the population be after 2 years?
- 15.What is the difference between the compound interest and the simple interest on ₹27200 at 10% per year for 2 years (in ₹)?
- 16.A town has 3000 people. The population grows by 10% every year. What will the population be after 1 year?
- 17.What amount will ₹16000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
- 19.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
- 20.Find the compound interest on ₹9600 at 5% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
- 22.What amount will ₹45600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹29200 at 5% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹24000 at 15% per year for 1 year, compounded every year (in ₹).
- 26.What amount will ₹9200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 27.What amount will ₹43200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 28.What amount will ₹52200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 29.A town has 21000 people. The population grows by 10% every year. What will the population be after 2 years?
- 30.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 31.What amount will ₹3000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹5100 at 20% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹2800 at 5% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 37.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
- 38.What is the difference between the compound interest and the simple interest on ₹8800 at 15% per year for 2 years (in ₹)?
- 39.A town has 40400 people. The population grows by 5% every year. What will the population be after 2 years?
- 40.A scooter is worth ₹10800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
Answer key
- 23328
- 72
- 12501
- 4050
- 336
- 48
- 2880
- 7018
- 5080
- 240
- 1800
- 68125
- 15300
- 56784
- 272
- 3300
- 18400
- 204
- 17496
- 984
- 10261
- 47880
- 145
- 2993
- 3600
- 11132
- 84375
- 56376
- 25410
- 8827
- 3240
- 1632
- 204
- 287
- 1188
- 20577
- 11664
- 198
- 44541
- 9936
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