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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 526 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹8800 grow to in 1 year at 25% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹27700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  3. 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹21900 at 10% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  6. 6.What amount will ₹23800 grow to in 2 years at 10% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
  8. 8.What amount will ₹47100 grow to in 1 year at 5% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹57100 at 12% per year for 1 year, compounded every year (in ₹).
  10. 10.What amount will ₹36800 grow to in 2 years at 15% per year compound interest (in ₹)?
  11. 11.A town has 2900 people. The population grows by 20% every year. What will the population be after 2 years?
  12. 12.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹6900 at 20% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
  15. 15.A town has 28000 people. The population grows by 10% every year. What will the population be after 3 years?
  16. 16.What amount will ₹32600 grow to in 1 year at 12% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹4000 at 20% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹14100 at 8% per year for 1 year, compounded every year (in ₹).
  19. 19.What amount will ₹14600 grow to in 1 year at 12% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹40000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹6000 at 20% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹12100 at 20% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹3400 at 25% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
  26. 26.What amount will ₹22900 grow to in 2 years at 10% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹35300 at 20% per year for 2 years, compounded every year (in ₹).
  28. 28.What amount will ₹23200 grow to in 2 years at 5% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹37300 at 20% per year for 2 years (in ₹)?
  30. 30.What amount will ₹12800 grow to in 2 years at 5% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  34. 34.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
  35. 35.A town has 8600 people. The population grows by 8% every year. What will the population be after 1 year?
  36. 36.A scooter is worth ₹7100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  37. 37.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
  38. 38.A town has 16400 people. The population grows by 5% every year. What will the population be after 1 year?
  39. 39.What amount will ₹32600 grow to in 2 years at 10% per year compound interest (in ₹)?
  40. 40.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?

Answer key

  1. 11000
  2. 25484
  3. 8334
  4. 4599
  5. 36501
  6. 28798
  7. 32025
  8. 49455
  9. 6852
  10. 48668
  11. 4176
  12. 48
  13. 1380
  14. 125
  15. 37268
  16. 36512
  17. 160
  18. 1128
  19. 16352
  20. 29160
  21. 240
  22. 484
  23. 846
  24. 850
  25. 19529
  26. 27709
  27. 15532
  28. 25578
  29. 1492
  30. 14112
  31. 8268
  32. 18816
  33. 192
  34. 67881
  35. 9288
  36. 5680
  37. 22875
  38. 17220
  39. 39446
  40. 48668

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