Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹8800 grow to in 1 year at 25% per year compound interest (in ₹)?
- 2.A scooter is worth ₹27700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹21900 at 10% per year for 2 years, compounded every year (in ₹).
- 5.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 6.What amount will ₹23800 grow to in 2 years at 10% per year compound interest (in ₹)?
- 7.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
- 8.What amount will ₹47100 grow to in 1 year at 5% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹57100 at 12% per year for 1 year, compounded every year (in ₹).
- 10.What amount will ₹36800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 11.A town has 2900 people. The population grows by 20% every year. What will the population be after 2 years?
- 12.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹6900 at 20% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
- 15.A town has 28000 people. The population grows by 10% every year. What will the population be after 3 years?
- 16.What amount will ₹32600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹4000 at 20% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹14100 at 8% per year for 1 year, compounded every year (in ₹).
- 19.What amount will ₹14600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 20.A scooter is worth ₹40000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹6000 at 20% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹12100 at 20% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹3400 at 25% per year for 1 year, compounded every year (in ₹).
- 25.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
- 26.What amount will ₹22900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹35300 at 20% per year for 2 years, compounded every year (in ₹).
- 28.What amount will ₹23200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹37300 at 20% per year for 2 years (in ₹)?
- 30.What amount will ₹12800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
- 32.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
- 34.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
- 35.A town has 8600 people. The population grows by 8% every year. What will the population be after 1 year?
- 36.A scooter is worth ₹7100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 37.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
- 38.A town has 16400 people. The population grows by 5% every year. What will the population be after 1 year?
- 39.What amount will ₹32600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 40.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
Answer key
- 11000
- 25484
- 8334
- 4599
- 36501
- 28798
- 32025
- 49455
- 6852
- 48668
- 4176
- 48
- 1380
- 125
- 37268
- 36512
- 160
- 1128
- 16352
- 29160
- 240
- 484
- 846
- 850
- 19529
- 27709
- 15532
- 25578
- 1492
- 14112
- 8268
- 18816
- 192
- 67881
- 9288
- 5680
- 22875
- 17220
- 39446
- 48668
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