Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 529 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹56700 at 10% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹19000 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹5800 at 10% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹18800 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹15600 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹2000 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹25400 at 10% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹36000 at 15% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
12. 12.What is the difference between the compound interest and the simple interest on ₹57200 at 10% per year for 2 years (in ₹)?
13. 13.What amount will ₹35000 grow to in 3 years at 10% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹54800 at 20% per year for 2 years (in ₹)?
16. 16.What amount will ₹25000 grow to in 1 year at 10% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹18000 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
19. 19.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹35700 at 8% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 29200 people. The population grows by 25% every year. What will the population be after 2 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹8400 at 25% per year for 2 years (in ₹)?
24. 24.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
25. 25.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
26. 26.What amount will ₹46500 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹53700 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹13000 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹38900 grow to in 1 year at 25% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹44500 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹20800 at 15% per year for 2 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹11600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
35. 35.Find the compound interest on ₹24800 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹50600 at 10% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 28400 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹52000 at 20% per year for 2 years (in ₹)?
40. 40.What amount will ₹20800 grow to in 3 years at 25% per year compound interest (in ₹)?

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