Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 532 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹6000 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 15800 people. The population grows by 20% every year. What will the population be after 2 years?
3. 3.Find the compound interest on ₹15100 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹28500 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹32800 at 10% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
8. 8.A town has 14200 people. The population grows by 20% every year. What will the population be after 1 year?
9. 9.What amount will ₹56000 grow to in 3 years at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹49800 at 20% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹25500 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹33200 at 5% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹2800 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹59800 at 15% per year for 1 year, compounded every year (in ₹).
16. 16.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
17. 17.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹25900 at 12% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹23100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹20000 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹54800 at 5% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹31000 at 8% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹59700 at 20% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹35100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
29. 29.A town has 53000 people. The population grows by 10% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹16100 at 5% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹35900 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹49500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
33. 33.Find the compound interest on ₹37600 at 25% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹31200 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.A scooter is worth ₹9200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹9100 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹56500 grow to in 2 years at 10% per year compound interest (in ₹)?

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