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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 534 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹3000 at 12% per year for 1 year, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹47500 at 20% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹27400 at 10% per year for 2 years (in ₹)?
  5. 5.What amount will ₹48300 grow to in 1 year at 4% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  7. 7.What amount will ₹56000 grow to in 1 year at 15% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹31200 at 25% per year for 1 year, compounded every year (in ₹).
  9. 9.A town has 14400 people. The population grows by 10% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹30600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  12. 12.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
  13. 13.What amount will ₹17900 grow to in 1 year at 20% per year compound interest (in ₹)?
  14. 14.A scooter is worth ₹28900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  15. 15.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
  16. 16.What amount will ₹52800 grow to in 2 years at 5% per year compound interest (in ₹)?
  17. 17.What amount will ₹21600 grow to in 2 years at 15% per year compound interest (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹3000 at 10% per year for 2 years (in ₹)?
  19. 19.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
  20. 20.A town has 42400 people. The population grows by 25% every year. What will the population be after 1 year?
  21. 21.What amount will ₹10600 grow to in 2 years at 10% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹44800 at 10% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
  26. 26.A town has 16100 people. The population grows by 4% every year. What will the population be after 1 year?
  27. 27.A scooter is worth ₹58600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  28. 28.A town has 3500 people. The population grows by 20% every year. What will the population be after 3 years?
  29. 29.A town has 18700 people. The population grows by 15% every year. What will the population be after 1 year?
  30. 30.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
  31. 31.What amount will ₹56900 grow to in 1 year at 5% per year compound interest (in ₹)?
  32. 32.A scooter is worth ₹59200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  33. 33.A town has 57600 people. The population grows by 25% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹36800 at 10% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
  36. 36.A town has 24800 people. The population grows by 5% every year. What will the population be after 1 year?
  37. 37.Find the compound interest on ₹55400 at 15% per year for 1 year, compounded every year (in ₹).
  38. 38.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹43500 at 20% per year for 3 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?

Answer key

  1. 360
  2. 2000
  3. 1900
  4. 274
  5. 50232
  6. 44
  7. 64400
  8. 7800
  9. 17424
  10. 1275
  11. 27540
  12. 17496
  13. 21480
  14. 27455
  15. 15250
  16. 58212
  17. 28566
  18. 30
  19. 58320
  20. 53000
  21. 12826
  22. 320
  23. 448
  24. 252
  25. 75
  26. 16744
  27. 56256
  28. 6048
  29. 21505
  30. 1020
  31. 59745
  32. 37888
  33. 90000
  34. 3680
  35. 1350
  36. 26040
  37. 8310
  38. 59584
  39. 31668
  40. 40

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