Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.Find the compound interest on ₹3000 at 12% per year for 1 year, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹47500 at 20% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹27400 at 10% per year for 2 years (in ₹)?
- 5.What amount will ₹48300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 7.What amount will ₹56000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹31200 at 25% per year for 1 year, compounded every year (in ₹).
- 9.A town has 14400 people. The population grows by 10% every year. What will the population be after 2 years?
- 10.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹30600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 12.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
- 13.What amount will ₹17900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 14.A scooter is worth ₹28900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 15.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
- 16.What amount will ₹52800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 17.What amount will ₹21600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹3000 at 10% per year for 2 years (in ₹)?
- 19.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 20.A town has 42400 people. The population grows by 25% every year. What will the population be after 1 year?
- 21.What amount will ₹10600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹44800 at 10% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
- 26.A town has 16100 people. The population grows by 4% every year. What will the population be after 1 year?
- 27.A scooter is worth ₹58600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 28.A town has 3500 people. The population grows by 20% every year. What will the population be after 3 years?
- 29.A town has 18700 people. The population grows by 15% every year. What will the population be after 1 year?
- 30.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
- 31.What amount will ₹56900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 32.A scooter is worth ₹59200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 33.A town has 57600 people. The population grows by 25% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹36800 at 10% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
- 36.A town has 24800 people. The population grows by 5% every year. What will the population be after 1 year?
- 37.Find the compound interest on ₹55400 at 15% per year for 1 year, compounded every year (in ₹).
- 38.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹43500 at 20% per year for 3 years, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
Answer key
- 360
- 2000
- 1900
- 274
- 50232
- 44
- 64400
- 7800
- 17424
- 1275
- 27540
- 17496
- 21480
- 27455
- 15250
- 58212
- 28566
- 30
- 58320
- 53000
- 12826
- 320
- 448
- 252
- 75
- 16744
- 56256
- 6048
- 21505
- 1020
- 59745
- 37888
- 90000
- 3680
- 1350
- 26040
- 8310
- 59584
- 31668
- 40
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