Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 539 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹8000 at 10% per year for 2 years, compounded every year (in ₹).
2. 2.A scooter is worth ₹2500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
3. 3.What amount will ₹38000 grow to in 3 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹14100 at 20% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹2400 at 25% per year for 2 years, compounded every year (in ₹).
6. 6.A town has 57700 people. The population grows by 20% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹33400 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.A town has 16000 people. The population grows by 25% every year. What will the population be after 2 years?
10. 10.A town has 23600 people. The population grows by 15% every year. What will the population be after 2 years?
11. 11.Find the compound interest on ₹20800 at 5% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹30700 at 25% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 43300 people. The population grows by 4% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹24100 at 10% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹44900 grow to in 1 year at 5% per year compound interest (in ₹)?
16. 16.A scooter is worth ₹4500. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹21000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹11200 at 15% per year for 2 years (in ₹)?
20. 20.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹14000 at 15% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹14200 at 4% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹53800 at 10% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹5200 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹8300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
29. 29.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹22200 at 10% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹16600 at 10% per year for 2 years (in ₹)?
32. 32.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
34. 34.A town has 46000 people. The population grows by 10% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹12200 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹19200 at 5% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
38. 38.A town has 46000 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹22400 at 15% per year for 2 years (in ₹)?
40. 40.What amount will ₹23200 grow to in 2 years at 15% per year compound interest (in ₹)?

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