Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 542 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹9200 at 5% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹58500 at 4% per year for 1 year, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹44600 at 10% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹30500. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
7. 7.What amount will ₹54000 grow to in 3 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹16600 at 10% per year for 2 years (in ₹)?
9. 9.A scooter is worth ₹40400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
10. 10.A town has 52800 people. The population grows by 25% every year. What will the population be after 3 years?
11. 11.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
12. 12.What amount will ₹3200 grow to in 1 year at 5% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹55200 at 5% per year for 2 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹36500 at 20% per year for 3 years, compounded every year (in ₹).
15. 15.A scooter is worth ₹10500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
16. 16.Find the compound interest on ₹48000 at 25% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹22700 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
20. 20.Find the compound interest on ₹4300 at 4% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹26000 at 25% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
23. 23.Find the compound interest on ₹4500 at 12% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
26. 26.What amount will ₹6800 grow to in 2 years at 15% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹45100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
28. 28.Find the compound interest on ₹57700 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.A scooter is worth ₹32500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
30. 30.What amount will ₹16000 grow to in 2 years at 10% per year compound interest (in ₹)?
31. 31.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹28800 at 25% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹16700 at 12% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹8000 grow to in 3 years at 20% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹29500 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹46400 at 15% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹21100 at 12% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹55000 at 20% per year for 3 years, compounded every year (in ₹).
40. 40.A town has 47900 people. The population grows by 10% every year. What will the population be after 1 year?

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