Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 55 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 24400 people. The population grows by 5% every year. What will the population be after 2 years?
2. 2.What amount will ₹50000 grow to in 2 years at 15% per year compound interest (in ₹)?
3. 3.A town has 44700 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹6800 at 25% per year for 1 year, compounded every year (in ₹).
5. 5.What amount will ₹15500 grow to in 1 year at 15% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹34700 at 20% per year for 2 years (in ₹)?
7. 7.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹19500 at 20% per year for 1 year, compounded every year (in ₹).
10. 10.A scooter is worth ₹14400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
11. 11.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
13. 13.A town has 42700 people. The population grows by 20% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹19500 at 4% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
16. 16.What amount will ₹14400 grow to in 2 years at 25% per year compound interest (in ₹)?
17. 17.A town has 12400 people. The population grows by 20% every year. What will the population be after 2 years?
18. 18.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
20. 20.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
21. 21.A scooter is worth ₹32600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹11000 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.What amount will ₹47300 grow to in 1 year at 5% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹8100 at 20% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹51300 at 10% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹41000 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹39200 grow to in 2 years at 25% per year compound interest (in ₹)?
29. 29.What amount will ₹17500 grow to in 1 year at 4% per year compound interest (in ₹)?
30. 30.What amount will ₹4800 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹34400 at 15% per year for 2 years (in ₹)?
32. 32.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
33. 33.A scooter is worth ₹18600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
34. 34.Find the compound interest on ₹13500 at 10% per year for 1 year, compounded every year (in ₹).
35. 35.What amount will ₹30700 grow to in 1 year at 5% per year compound interest (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
37. 37.What amount will ₹47800 grow to in 2 years at 20% per year compound interest (in ₹)?
38. 38.A town has 28000 people. The population grows by 5% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹15300 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets