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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 551 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹17900 at 20% per year for 1 year, compounded every year (in ₹).
  2. 2.A scooter is worth ₹20500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  3. 3.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹17500 at 20% per year for 3 years, compounded every year (in ₹).
  5. 5.A scooter is worth ₹33200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹12300 at 4% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
  9. 9.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
  10. 10.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  11. 11.What amount will ₹18200 grow to in 1 year at 4% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹33600 at 5% per year for 2 years (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹34400 at 10% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
  15. 15.A scooter is worth ₹29200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  16. 16.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹20100 at 5% per year for 1 year, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹59200 at 25% per year for 2 years, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹14500 at 20% per year for 3 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹10400 at 5% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹9600 at 20% per year for 1 year, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹31500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  25. 25.Find the compound interest on ₹18000 at 5% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹4800 grow to in 2 years at 15% per year compound interest (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹22500 at 20% per year for 2 years (in ₹)?
  28. 28.What amount will ₹44800 grow to in 1 year at 20% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹8800 at 5% per year for 2 years (in ₹)?
  30. 30.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  31. 31.A scooter is worth ₹58900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  32. 32.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹10000 at 25% per year for 2 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  35. 35.A town has 52000 people. The population grows by 10% every year. What will the population be after 3 years?
  36. 36.What amount will ₹45000 grow to in 2 years at 8% per year compound interest (in ₹)?
  37. 37.A town has 37800 people. The population grows by 12% every year. What will the population be after 1 year?
  38. 38.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
  39. 39.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 3580
  2. 19475
  3. 39650
  4. 12740
  5. 23987
  6. 73
  7. 492
  8. 4575
  9. 87500
  10. 1261
  11. 18928
  12. 84
  13. 344
  14. 3641
  15. 26353
  16. 18834
  17. 1005
  18. 2522
  19. 33300
  20. 10556
  21. 1066
  22. 1920
  23. 92
  24. 16128
  25. 900
  26. 6348
  27. 900
  28. 53760
  29. 22
  30. 48013
  31. 50065
  32. 7072
  33. 5625
  34. 12
  35. 69212
  36. 52488
  37. 42336
  38. 30613
  39. 100000
  40. 18205

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