Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹17900 at 20% per year for 1 year, compounded every year (in ₹).
- 2.A scooter is worth ₹20500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 3.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹17500 at 20% per year for 3 years, compounded every year (in ₹).
- 5.A scooter is worth ₹33200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹12300 at 4% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
- 9.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
- 10.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 11.What amount will ₹18200 grow to in 1 year at 4% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹33600 at 5% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹34400 at 10% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
- 15.A scooter is worth ₹29200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 16.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹20100 at 5% per year for 1 year, compounded every year (in ₹).
- 18.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹59200 at 25% per year for 2 years, compounded every year (in ₹).
- 20.Find the compound interest on ₹14500 at 20% per year for 3 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹10400 at 5% per year for 2 years, compounded every year (in ₹).
- 22.Find the compound interest on ₹9600 at 20% per year for 1 year, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 24.A scooter is worth ₹31500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 25.Find the compound interest on ₹18000 at 5% per year for 1 year, compounded every year (in ₹).
- 26.What amount will ₹4800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹22500 at 20% per year for 2 years (in ₹)?
- 28.What amount will ₹44800 grow to in 1 year at 20% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹8800 at 5% per year for 2 years (in ₹)?
- 30.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 31.A scooter is worth ₹58900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 32.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹10000 at 25% per year for 2 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
- 35.A town has 52000 people. The population grows by 10% every year. What will the population be after 3 years?
- 36.What amount will ₹45000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 37.A town has 37800 people. The population grows by 12% every year. What will the population be after 1 year?
- 38.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 39.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).
Answer key
- 3580
- 19475
- 39650
- 12740
- 23987
- 73
- 492
- 4575
- 87500
- 1261
- 18928
- 84
- 344
- 3641
- 26353
- 18834
- 1005
- 2522
- 33300
- 10556
- 1066
- 1920
- 92
- 16128
- 900
- 6348
- 900
- 53760
- 22
- 48013
- 50065
- 7072
- 5625
- 12
- 69212
- 52488
- 42336
- 30613
- 100000
- 18205
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets