Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 554 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
3. 3.What amount will ₹40400 grow to in 2 years at 5% per year compound interest (in ₹)?
4. 4.A scooter is worth ₹42000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
5. 5.Find the compound interest on ₹45800 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹50000 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹53100 at 12% per year for 1 year, compounded every year (in ₹).
8. 8.A town has 31200 people. The population grows by 10% every year. What will the population be after 2 years?
9. 9.A town has 9700 people. The population grows by 8% every year. What will the population be after 1 year?
10. 10.What is the difference between the compound interest and the simple interest on ₹26600 at 10% per year for 2 years (in ₹)?
11. 11.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹28800 at 20% per year for 2 years (in ₹)?
13. 13.A town has 16600 people. The population grows by 4% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹15500 at 15% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹56600 at 8% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹58800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
18. 18.What amount will ₹10600 grow to in 2 years at 20% per year compound interest (in ₹)?
19. 19.What amount will ₹32800 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹11400 at 4% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹54900 at 20% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹18400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
24. 24.A scooter is worth ₹22900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
29. 29.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
30. 30.A scooter is worth ₹39500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
31. 31.What amount will ₹31900 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.What amount will ₹2900 grow to in 1 year at 5% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹27000 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
35. 35.What amount will ₹13100 grow to in 1 year at 15% per year compound interest (in ₹)?
36. 36.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
37. 37.What amount will ₹3200 grow to in 3 years at 25% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹57600 at 15% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).

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