← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 559 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A town has 5900 people. The population grows by 12% every year. What will the population be after 1 year?
  2. 2.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  3. 3.What amount will ₹23300 grow to in 1 year at 8% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹33700 at 10% per year for 2 years (in ₹)?
  5. 5.What amount will ₹17600 grow to in 1 year at 20% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
  7. 7.What amount will ₹41100 grow to in 1 year at 12% per year compound interest (in ₹)?
  8. 8.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹54600 at 10% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹38500 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹38300 at 12% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹23600 at 20% per year for 1 year, compounded every year (in ₹).
  16. 16.What amount will ₹40400 grow to in 1 year at 12% per year compound interest (in ₹)?
  17. 17.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  18. 18.What amount will ₹13500 grow to in 1 year at 25% per year compound interest (in ₹)?
  19. 19.What amount will ₹31300 grow to in 1 year at 5% per year compound interest (in ₹)?
  20. 20.What amount will ₹48600 grow to in 1 year at 10% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹48400 at 12% per year for 1 year, compounded every year (in ₹).
  22. 22.A scooter is worth ₹44700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹33500 at 10% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹15900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  25. 25.A town has 14200 people. The population grows by 8% every year. What will the population be after 1 year?
  26. 26.Find the compound interest on ₹57200 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹13100 at 4% per year for 1 year, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹31600 grow to in 1 year at 12% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹52200 at 5% per year for 1 year, compounded every year (in ₹).
  32. 32.What amount will ₹21600 grow to in 2 years at 25% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹52000 at 20% per year for 3 years, compounded every year (in ₹).
  35. 35.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  36. 36.A scooter is worth ₹30800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  37. 37.What amount will ₹54500 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.A scooter is worth ₹57800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹52400 at 25% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?

Answer key

  1. 6608
  2. 18522
  3. 25164
  4. 337
  5. 21120
  6. 101
  7. 46032
  8. 12544
  9. 546
  10. 333
  11. 3850
  12. 9408
  13. 4596
  14. 30500
  15. 4720
  16. 45248
  17. 12167
  18. 16875
  19. 32865
  20. 53460
  21. 5808
  22. 33525
  23. 335
  24. 14628
  25. 15336
  26. 12012
  27. 524
  28. 29169
  29. 35392
  30. 16881
  31. 2610
  32. 33750
  33. 304
  34. 37856
  35. 13718
  36. 27797
  37. 65945
  38. 43350
  39. 3275
  40. 17

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets