Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 564 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹39000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹44400 at 15% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹3400 at 5% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹37300 grow to in 1 year at 15% per year compound interest (in ₹)?
5. 5.What amount will ₹57400 grow to in 1 year at 4% per year compound interest (in ₹)?
6. 6.What amount will ₹8500 grow to in 3 years at 20% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹8400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
8. 8.Find the compound interest on ₹55200 at 25% per year for 2 years, compounded every year (in ₹).
9. 9.A town has 5200 people. The population grows by 10% every year. What will the population be after 2 years?
10. 10.A scooter is worth ₹17000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
11. 11.Find the compound interest on ₹7200 at 25% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹52900 at 25% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
14. 14.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹26000 at 20% per year for 2 years (in ₹)?
16. 16.A town has 49900 people. The population grows by 8% every year. What will the population be after 1 year?
17. 17.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹42000 at 25% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 50400 people. The population grows by 15% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹44900 at 10% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹45000 grow to in 2 years at 4% per year compound interest (in ₹)?
22. 22.What amount will ₹44000 grow to in 3 years at 10% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
24. 24.A town has 45000 people. The population grows by 10% every year. What will the population be after 3 years?
25. 25.What amount will ₹22000 grow to in 3 years at 10% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹49400 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.What amount will ₹2100 grow to in 1 year at 5% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹43200 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
32. 32.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹54300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹57200 at 15% per year for 2 years (in ₹)?
36. 36.A town has 54000 people. The population grows by 15% every year. What will the population be after 2 years?
37. 37.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹49000 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.A town has 48400 people. The population grows by 25% every year. What will the population be after 1 year?
40. 40.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?

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