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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 566 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹6300 at 20% per year for 2 years (in ₹)?
  3. 3.What amount will ₹32400 grow to in 2 years at 10% per year compound interest (in ₹)?
  4. 4.What amount will ₹23600 grow to in 2 years at 25% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹21900 at 10% per year for 1 year, compounded every year (in ₹).
  6. 6.A scooter is worth ₹15200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.A town has 43700 people. The population grows by 10% every year. What will the population be after 2 years?
  8. 8.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
  9. 9.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹22100 at 10% per year for 2 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹7000 at 15% per year for 1 year, compounded every year (in ₹).
  12. 12.What amount will ₹56300 grow to in 1 year at 15% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  14. 14.What amount will ₹41000 grow to in 2 years at 10% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
  16. 16.A town has 57000 people. The population grows by 10% every year. What will the population be after 3 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹18700 at 10% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹46200 at 20% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  23. 23.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  24. 24.What amount will ₹29900 grow to in 2 years at 10% per year compound interest (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹45200 at 25% per year for 2 years (in ₹)?
  26. 26.What amount will ₹31200 grow to in 2 years at 25% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹34800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  28. 28.A scooter is worth ₹15000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  29. 29.Find the compound interest on ₹44000 at 25% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹54200 at 8% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹36400 grow to in 2 years at 25% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  33. 33.What amount will ₹25500 grow to in 3 years at 20% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹31400 at 10% per year for 2 years (in ₹)?
  35. 35.A town has 50000 people. The population grows by 4% every year. What will the population be after 2 years?
  36. 36.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹10400 at 4% per year for 1 year, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  40. 40.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?

Answer key

  1. 6360
  2. 252
  3. 39204
  4. 36875
  5. 2190
  6. 10982
  7. 52877
  8. 240
  9. 47275
  10. 4641
  11. 1050
  12. 64745
  13. 29169
  14. 49610
  15. 80
  16. 75867
  17. 187
  18. 24400
  19. 1848
  20. 504
  21. 68
  22. 3783
  23. 29624
  24. 36179
  25. 2825
  26. 48750
  27. 31407
  28. 11250
  29. 24750
  30. 4336
  31. 56875
  32. 72
  33. 44064
  34. 314
  35. 54080
  36. 27783
  37. 416
  38. 48
  39. 756
  40. 3125

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