Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹12900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 2.A scooter is worth ₹10500. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 3.A scooter is worth ₹29500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹29600 at 25% per year for 2 years (in ₹)?
- 5.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.A town has 26400 people. The population grows by 5% every year. What will the population be after 2 years?
- 7.Find the compound interest on ₹8000 at 20% per year for 3 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹28500 at 25% per year for 1 year, compounded every year (in ₹).
- 9.Find the compound interest on ₹17600 at 20% per year for 1 year, compounded every year (in ₹).
- 10.A town has 59200 people. The population grows by 25% every year. What will the population be after 1 year?
- 11.What amount will ₹60000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
- 13.A scooter is worth ₹40000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 14.Find the compound interest on ₹24100 at 12% per year for 1 year, compounded every year (in ₹).
- 15.What amount will ₹17300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹36900 at 10% per year for 2 years, compounded every year (in ₹).
- 18.What amount will ₹7600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹53800 at 10% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
- 22.Find the compound interest on ₹29300 at 15% per year for 1 year, compounded every year (in ₹).
- 23.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹45000 at 4% per year for 2 years, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 26.A scooter is worth ₹42700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 27.Find the compound interest on ₹32000 at 10% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
- 29.What amount will ₹59500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 30.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹30800 at 25% per year for 2 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
- 33.What amount will ₹16000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 38.A town has 15200 people. The population grows by 25% every year. What will the population be after 2 years?
- 39.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 40.A scooter is worth ₹2000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
Answer key
- 9675
- 7875
- 26550
- 1850
- 9261
- 29106
- 5824
- 7125
- 3520
- 74000
- 93750
- 92
- 16875
- 2892
- 19030
- 32
- 7749
- 8512
- 538
- 68
- 993
- 4395
- 8334
- 3672
- 336
- 34587
- 6720
- 13725
- 102816
- 90625
- 17325
- 3328
- 23040
- 160
- 2040
- 1261
- 108
- 23750
- 576
- 1900
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