Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 570 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹12300 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹2400 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
5. 5.What amount will ₹28000 grow to in 3 years at 20% per year compound interest (in ₹)?
6. 6.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹30400 at 5% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
9. 9.A town has 40400 people. The population grows by 15% every year. What will the population be after 2 years?
10. 10.What amount will ₹26900 grow to in 1 year at 4% per year compound interest (in ₹)?
11. 11.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
12. 12.What amount will ₹12000 grow to in 1 year at 4% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹3200 at 4% per year for 1 year, compounded every year (in ₹).
14. 14.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
15. 15.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹4500 at 12% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹10500 grow to in 1 year at 4% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹3800 at 10% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹20400 at 5% per year for 2 years (in ₹)?
22. 22.What amount will ₹9200 grow to in 2 years at 20% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
25. 25.What amount will ₹46000 grow to in 3 years at 10% per year compound interest (in ₹)?
26. 26.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹12400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
28. 28.What amount will ₹59100 grow to in 1 year at 25% per year compound interest (in ₹)?
29. 29.What amount will ₹9600 grow to in 2 years at 15% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹36900 at 10% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹5000 at 20% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹40200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
34. 34.Find the compound interest on ₹17200 at 5% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
38. 38.A scooter is worth ₹25900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
39. 39.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).

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