Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹39200 at 25% per year for 2 years, compounded every year (in ₹).
- 2.A scooter is worth ₹7600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 4.A scooter is worth ₹25700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 5.A town has 43600 people. The population grows by 5% every year. What will the population be after 2 years?
- 6.A scooter is worth ₹17400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹58000 at 15% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹5600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 9.A scooter is worth ₹33000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 10.A town has 48600 people. The population grows by 10% every year. What will the population be after 1 year?
- 11.A scooter is worth ₹58800. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹56300 at 12% per year for 1 year, compounded every year (in ₹).
- 13.What amount will ₹36000 grow to in 2 years at 10% per year compound interest (in ₹)?
- 14.A scooter is worth ₹37400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 15.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 16.A scooter is worth ₹55000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 17.A scooter is worth ₹6700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 18.What amount will ₹4800 grow to in 2 years at 10% per year compound interest (in ₹)?
- 19.A scooter is worth ₹14700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 20.Find the compound interest on ₹5800 at 4% per year for 1 year, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹30000 at 25% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹15000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 24.A town has 24600 people. The population grows by 5% every year. What will the population be after 1 year?
- 25.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹9400 at 20% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹16800 at 5% per year for 1 year, compounded every year (in ₹).
- 28.Find the compound interest on ₹21800 at 8% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
- 30.Find the compound interest on ₹19200 at 10% per year for 2 years, compounded every year (in ₹).
- 31.What amount will ₹44800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 32.What amount will ₹18600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
- 34.A scooter is worth ₹58900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 35.A town has 56400 people. The population grows by 8% every year. What will the population be after 1 year?
- 36.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
- 38.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
- 39.Find the compound interest on ₹52300 at 4% per year for 1 year, compounded every year (in ₹).
- 40.Find the compound interest on ₹7400 at 12% per year for 1 year, compounded every year (in ₹).
Answer key
- 22050
- 6840
- 8334
- 23130
- 48069
- 13050
- 1305
- 3150
- 24750
- 53460
- 49980
- 6756
- 43560
- 30294
- 48013
- 50688
- 6432
- 5808
- 12936
- 232
- 252
- 1875
- 12696
- 25830
- 1261
- 376
- 840
- 1744
- 10812
- 4032
- 49280
- 19530
- 2979
- 54188
- 60912
- 32
- 114
- 24334
- 2092
- 888
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