Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 576 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹52400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹20800 at 15% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 33600 people. The population grows by 25% every year. What will the population be after 3 years?
6. 6.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
8. 8.What amount will ₹49700 grow to in 2 years at 20% per year compound interest (in ₹)?
9. 9.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹7500 at 4% per year for 1 year, compounded every year (in ₹).
11. 11.What amount will ₹44600 grow to in 1 year at 10% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹7600 at 15% per year for 2 years, compounded every year (in ₹).
13. 13.A scooter is worth ₹20000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
14. 14.A town has 5200 people. The population grows by 15% every year. What will the population be after 2 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹5000 at 20% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹14800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
17. 17.A town has 32000 people. The population grows by 10% every year. What will the population be after 2 years?
18. 18.Find the compound interest on ₹30000 at 15% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹57700 at 20% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
21. 21.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
23. 23.A town has 49900 people. The population grows by 12% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹17200 at 5% per year for 2 years (in ₹)?
25. 25.A town has 38800 people. The population grows by 15% every year. What will the population be after 2 years?
26. 26.Find the compound interest on ₹29500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
28. 28.A town has 13500 people. The population grows by 4% every year. What will the population be after 1 year?
29. 29.What is the difference between the compound interest and the simple interest on ₹44400 at 15% per year for 2 years (in ₹)?
30. 30.What amount will ₹24000 grow to in 3 years at 10% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹37200 at 5% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹15900 at 20% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹42500 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 31700 people. The population grows by 20% every year. What will the population be after 1 year?
35. 35.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
36. 36.What amount will ₹47600 grow to in 1 year at 12% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹46100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.A town has 42100 people. The population grows by 5% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹53200 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?

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