Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 580 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹35000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.A town has 2400 people. The population grows by 15% every year. What will the population be after 2 years?
3. 3.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹7600 at 5% per year for 2 years (in ₹)?
5. 5.A town has 33600 people. The population grows by 25% every year. What will the population be after 3 years?
6. 6.A town has 54400 people. The population grows by 25% every year. What will the population be after 2 years?
7. 7.A town has 30000 people. The population grows by 12% every year. What will the population be after 2 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
10. 10.What amount will ₹29600 grow to in 2 years at 25% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹19100 at 12% per year for 1 year, compounded every year (in ₹).
12. 12.A scooter is worth ₹29100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
13. 13.A scooter is worth ₹15800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
14. 14.What amount will ₹38800 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹59300 grow to in 1 year at 4% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹52800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
18. 18.A scooter is worth ₹29400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
19. 19.Find the compound interest on ₹3600 at 20% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹29500 at 10% per year for 2 years (in ₹)?
21. 21.What amount will ₹55600 grow to in 2 years at 25% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹22400 at 20% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹58500 at 25% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹14800 at 25% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹58300 at 20% per year for 1 year, compounded every year (in ₹).
29. 29.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.A scooter is worth ₹60000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹44800 at 15% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹41800 at 20% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹23000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
36. 36.A scooter is worth ₹52900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
37. 37.A town has 11000 people. The population grows by 10% every year. What will the population be after 3 years?
38. 38.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹6000 at 15% per year for 2 years, compounded every year (in ₹).

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