Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 586 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹28500 grow to in 1 year at 8% per year compound interest (in ₹)?
2. 2.A town has 7800 people. The population grows by 12% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹7500 at 20% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
6. 6.What amount will ₹33400 grow to in 2 years at 10% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹7500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹29800 at 10% per year for 2 years (in ₹)?
9. 9.A scooter is worth ₹57200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
10. 10.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
11. 11.What amount will ₹32000 grow to in 3 years at 20% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
13. 13.What amount will ₹7000 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹36500 at 10% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
16. 16.What amount will ₹3600 grow to in 2 years at 5% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹58700 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹43200 at 15% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 39400 people. The population grows by 12% every year. What will the population be after 1 year?
22. 22.What amount will ₹34000 grow to in 1 year at 5% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹16800 at 5% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹58400 grow to in 2 years at 10% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹11400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
26. 26.A scooter is worth ₹11500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹9200 at 5% per year for 2 years (in ₹)?
28. 28.A town has 17500 people. The population grows by 12% every year. What will the population be after 2 years?
29. 29.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.What amount will ₹59200 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹45300 at 15% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
35. 35.A town has 41100 people. The population grows by 5% every year. What will the population be after 1 year?
36. 36.A scooter is worth ₹2100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
37. 37.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹2000 at 5% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?

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