Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 2.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
- 3.Find the compound interest on ₹6900 at 5% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹11100 at 4% per year for 1 year, compounded every year (in ₹).
- 5.A town has 11000 people. The population grows by 8% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹2500 at 15% per year for 1 year, compounded every year (in ₹).
- 7.A town has 11200 people. The population grows by 15% every year. What will the population be after 2 years?
- 8.Find the compound interest on ₹15400 at 5% per year for 1 year, compounded every year (in ₹).
- 9.A town has 13000 people. The population grows by 20% every year. What will the population be after 1 year?
- 10.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹47500 at 12% per year for 2 years, compounded every year (in ₹).
- 12.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 13.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
- 14.Find the compound interest on ₹16600 at 8% per year for 1 year, compounded every year (in ₹).
- 15.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹10400 at 15% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 18.A scooter is worth ₹59700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹36600 at 20% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹15200 at 25% per year for 2 years (in ₹)?
- 22.What amount will ₹57000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹2000 at 15% per year for 2 years, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹33900 at 10% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
- 28.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹10700 at 12% per year for 1 year, compounded every year (in ₹).
- 30.A town has 54100 people. The population grows by 5% every year. What will the population be after 1 year?
- 31.A town has 13700 people. The population grows by 12% every year. What will the population be after 1 year?
- 32.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
- 33.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
- 34.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 35.A town has 47500 people. The population grows by 12% every year. What will the population be after 2 years?
- 36.Find the compound interest on ₹3400 at 4% per year for 1 year, compounded every year (in ₹).
- 37.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 38.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹29000 at 4% per year for 1 year, compounded every year (in ₹).
Answer key
- 4167
- 43904
- 345
- 444
- 11880
- 375
- 14812
- 770
- 15600
- 37044
- 12084
- 44528
- 10923
- 1328
- 2662
- 234
- 7566
- 50745
- 828
- 1464
- 950
- 59850
- 3350
- 645
- 648
- 339
- 3400
- 85169
- 1284
- 56805
- 15344
- 288
- 9261
- 72
- 59584
- 136
- 29624
- 2522
- 408
- 1160
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