Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 591 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 54800 people. The population grows by 15% every year. What will the population be after 1 year?
2. 2.Find the compound interest on ₹35600 at 25% per year for 1 year, compounded every year (in ₹).
3. 3.Find the compound interest on ₹50600 at 5% per year for 1 year, compounded every year (in ₹).
4. 4.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
5. 5.What amount will ₹47700 grow to in 2 years at 10% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹44400 at 15% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 37600 people. The population grows by 10% every year. What will the population be after 2 years?
8. 8.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
9. 9.What amount will ₹3200 grow to in 2 years at 5% per year compound interest (in ₹)?
10. 10.What amount will ₹2500 grow to in 2 years at 10% per year compound interest (in ₹)?
11. 11.A town has 15100 people. The population grows by 12% every year. What will the population be after 1 year?
12. 12.A town has 24500 people. The population grows by 10% every year. What will the population be after 1 year?
13. 13.A town has 22900 people. The population grows by 5% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹25500 at 8% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹11700 grow to in 1 year at 25% per year compound interest (in ₹)?
16. 16.What amount will ₹6700 grow to in 1 year at 20% per year compound interest (in ₹)?
17. 17.A town has 26900 people. The population grows by 10% every year. What will the population be after 2 years?
18. 18.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹23800 grow to in 1 year at 12% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
21. 21.A town has 3200 people. The population grows by 15% every year. What will the population be after 2 years?
22. 22.Find the compound interest on ₹34400 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
24. 24.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹6200 at 4% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹49600 at 15% per year for 2 years (in ₹)?
28. 28.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹40400 at 5% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹33200 at 20% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹58500 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 17600 people. The population grows by 25% every year. What will the population be after 3 years?
34. 34.A town has 36000 people. The population grows by 20% every year. What will the population be after 3 years?
35. 35.What amount will ₹57600 grow to in 3 years at 25% per year compound interest (in ₹)?
36. 36.What amount will ₹25600 grow to in 2 years at 10% per year compound interest (in ₹)?
37. 37.A town has 4200 people. The population grows by 20% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹4000 at 20% per year for 2 years, compounded every year (in ₹).
39. 39.What amount will ₹53800 grow to in 1 year at 10% per year compound interest (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?

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