Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 595 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹28500 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.What amount will ₹9600 grow to in 1 year at 5% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
5. 5.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹46400 at 25% per year for 2 years (in ₹)?
7. 7.A town has 9000 people. The population grows by 8% every year. What will the population be after 1 year?
8. 8.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
9. 9.A town has 28000 people. The population grows by 10% every year. What will the population be after 3 years?
10. 10.A town has 3700 people. The population grows by 15% every year. What will the population be after 1 year?
11. 11.Find the compound interest on ₹8000 at 20% per year for 3 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹31400 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
14. 14.A town has 2300 people. The population grows by 8% every year. What will the population be after 1 year?
15. 15.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
16. 16.What is the difference between the compound interest and the simple interest on ₹53700 at 10% per year for 2 years (in ₹)?
17. 17.A town has 6300 people. The population grows by 15% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹28000 at 20% per year for 3 years, compounded every year (in ₹).
19. 19.A town has 15200 people. The population grows by 25% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹7500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
24. 24.What amount will ₹21000 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.A town has 9500 people. The population grows by 20% every year. What will the population be after 3 years?
26. 26.What amount will ₹47500 grow to in 1 year at 25% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
28. 28.A scooter is worth ₹56000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹37400 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.A scooter is worth ₹26800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
34. 34.What amount will ₹15800 grow to in 1 year at 4% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹58200 grow to in 1 year at 10% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹22800 at 10% per year for 2 years (in ₹)?
40. 40.A town has 46100 people. The population grows by 12% every year. What will the population be after 1 year?

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