Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 598 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹9200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
2. 2.A scooter is worth ₹24300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
3. 3.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
4. 4.A town has 7600 people. The population grows by 10% every year. What will the population be after 1 year?
5. 5.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
6. 6.Find the compound interest on ₹36700 at 20% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
8. 8.Find the compound interest on ₹49300 at 12% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹45500 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 17400 people. The population grows by 20% every year. What will the population be after 2 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹37800 at 5% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹8900 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.A town has 16300 people. The population grows by 10% every year. What will the population be after 2 years?
16. 16.What amount will ₹18200 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹36300 at 20% per year for 2 years (in ₹)?
18. 18.What amount will ₹7800 grow to in 2 years at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹44500 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
22. 22.A town has 41300 people. The population grows by 15% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹22300 at 10% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
29. 29.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
31. 31.A town has 29600 people. The population grows by 15% every year. What will the population be after 2 years?
32. 32.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹39900 at 12% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹25900 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹6000 at 25% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹29900 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 44200 people. The population grows by 10% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
40. 40.A scooter is worth ₹60000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?

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