Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 600 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 30900 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹53900 at 10% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
4. 4.A town has 11000 people. The population grows by 20% every year. What will the population be after 3 years?
5. 5.Find the compound interest on ₹11200 at 15% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹43600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
8. 8.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹6700 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.What amount will ₹6600 grow to in 2 years at 10% per year compound interest (in ₹)?
12. 12.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹9500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
14. 14.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
16. 16.A scooter is worth ₹20000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
18. 18.A town has 8200 people. The population grows by 10% every year. What will the population be after 1 year?
19. 19.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹31200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
22. 22.Find the compound interest on ₹35800 at 20% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹22400 grow to in 3 years at 25% per year compound interest (in ₹)?
24. 24.A town has 47500 people. The population grows by 4% every year. What will the population be after 2 years?
25. 25.What amount will ₹44600 grow to in 1 year at 8% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
28. 28.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
29. 29.Find the compound interest on ₹59600 at 15% per year for 2 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹22400 at 12% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
33. 33.What amount will ₹51100 grow to in 1 year at 20% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹24400 at 25% per year for 2 years (in ₹)?
35. 35.A town has 52100 people. The population grows by 12% every year. What will the population be after 1 year?
36. 36.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹15100 at 10% per year for 2 years (in ₹)?
38. 38.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹12900 at 12% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹51900 at 12% per year for 1 year, compounded every year (in ₹).

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