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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 607 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹16400 at 15% per year for 2 years (in ₹)?
  3. 3.A scooter is worth ₹12800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  4. 4.Find the compound interest on ₹19400 at 10% per year for 1 year, compounded every year (in ₹).
  5. 5.A scooter is worth ₹4100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  6. 6.Find the compound interest on ₹26000 at 15% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹44400 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹30400 at 15% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹22400 at 5% per year for 1 year, compounded every year (in ₹).
  11. 11.A town has 6000 people. The population grows by 10% every year. What will the population be after 3 years?
  12. 12.A town has 26400 people. The population grows by 25% every year. What will the population be after 2 years?
  13. 13.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹16600 at 20% per year for 2 years (in ₹)?
  15. 15.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹14400 at 5% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹56000 grow to in 3 years at 20% per year compound interest (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹16800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹5200 at 15% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹21000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  24. 24.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.What amount will ₹59900 grow to in 2 years at 10% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹33600 at 10% per year for 2 years (in ₹)?
  27. 27.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹37100 at 20% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
  31. 31.A scooter is worth ₹11500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  32. 32.What amount will ₹43100 grow to in 1 year at 4% per year compound interest (in ₹)?
  33. 33.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹32100 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.A town has 30300 people. The population grows by 20% every year. What will the population be after 2 years?
  37. 37.A scooter is worth ₹29300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  38. 38.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
  40. 40.A scooter is worth ₹27900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 92
  2. 369
  3. 11776
  4. 1940
  5. 2624
  6. 8385
  7. 24975
  8. 684
  9. 78
  10. 1120
  11. 7986
  12. 41250
  13. 12167
  14. 664
  15. 37856
  16. 1476
  17. 96768
  18. 137
  19. 15456
  20. 1188
  21. 1677
  22. 90
  23. 13440
  24. 25002
  25. 72479
  26. 336
  27. 4410
  28. 60
  29. 1484
  30. 108
  31. 11040
  32. 44824
  33. 46305
  34. 13902
  35. 8025
  36. 43632
  37. 27835
  38. 54080
  39. 16550
  40. 20925

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