Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹16400 at 15% per year for 2 years (in ₹)?
- 3.A scooter is worth ₹12800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 4.Find the compound interest on ₹19400 at 10% per year for 1 year, compounded every year (in ₹).
- 5.A scooter is worth ₹4100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 6.Find the compound interest on ₹26000 at 15% per year for 2 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹44400 at 25% per year for 2 years, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹30400 at 15% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹22400 at 5% per year for 1 year, compounded every year (in ₹).
- 11.A town has 6000 people. The population grows by 10% every year. What will the population be after 3 years?
- 12.A town has 26400 people. The population grows by 25% every year. What will the population be after 2 years?
- 13.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹16600 at 20% per year for 2 years (in ₹)?
- 15.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹14400 at 5% per year for 2 years, compounded every year (in ₹).
- 17.What amount will ₹56000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹16800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹5200 at 15% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹21000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 24.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 25.What amount will ₹59900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹33600 at 10% per year for 2 years (in ₹)?
- 27.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹37100 at 20% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 31.A scooter is worth ₹11500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 32.What amount will ₹43100 grow to in 1 year at 4% per year compound interest (in ₹)?
- 33.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
- 35.Find the compound interest on ₹32100 at 25% per year for 1 year, compounded every year (in ₹).
- 36.A town has 30300 people. The population grows by 20% every year. What will the population be after 2 years?
- 37.A scooter is worth ₹29300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 38.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.A scooter is worth ₹27900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
Answer key
- 92
- 369
- 11776
- 1940
- 2624
- 8385
- 24975
- 684
- 78
- 1120
- 7986
- 41250
- 12167
- 664
- 37856
- 1476
- 96768
- 137
- 15456
- 1188
- 1677
- 90
- 13440
- 25002
- 72479
- 336
- 4410
- 60
- 1484
- 108
- 11040
- 44824
- 46305
- 13902
- 8025
- 43632
- 27835
- 54080
- 16550
- 20925
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