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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 61 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
  3. 3.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
  4. 4.Find the compound interest on ₹41300 at 12% per year for 1 year, compounded every year (in ₹).
  5. 5.A scooter is worth ₹57600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  6. 6.A town has 4800 people. The population grows by 15% every year. What will the population be after 1 year?
  7. 7.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹18600 at 10% per year for 2 years (in ₹)?
  9. 9.A scooter is worth ₹15700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹22800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹2300 at 5% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹52500 at 20% per year for 2 years (in ₹)?
  14. 14.What amount will ₹47000 grow to in 1 year at 20% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹4400 at 5% per year for 2 years, compounded every year (in ₹).
  16. 16.What amount will ₹57900 grow to in 1 year at 15% per year compound interest (in ₹)?
  17. 17.A scooter is worth ₹33000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  18. 18.A scooter is worth ₹22200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  19. 19.What amount will ₹59200 grow to in 1 year at 25% per year compound interest (in ₹)?
  20. 20.What amount will ₹9600 grow to in 2 years at 25% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹2200 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹27100 at 4% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹40500 at 12% per year for 1 year, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  29. 29.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹19200 at 5% per year for 2 years (in ₹)?
  32. 32.A town has 46200 people. The population grows by 10% every year. What will the population be after 2 years?
  33. 33.What amount will ₹36800 grow to in 1 year at 25% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹26400 at 8% per year for 1 year, compounded every year (in ₹).
  39. 39.A scooter is worth ₹42200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹27200 at 25% per year for 2 years (in ₹)?

Answer key

  1. 612
  2. 150
  3. 18816
  4. 4956
  5. 48960
  6. 5520
  7. 630
  8. 186
  9. 13345
  10. 45
  11. 20064
  12. 115
  13. 2100
  14. 56400
  15. 451
  16. 66585
  17. 31680
  18. 19536
  19. 74000
  20. 15000
  21. 918
  22. 220
  23. 44225
  24. 396
  25. 62
  26. 1084
  27. 4860
  28. 756
  29. 34391
  30. 72
  31. 48
  32. 55902
  33. 46000
  34. 39168
  35. 48
  36. 12
  37. 9984
  38. 2112
  39. 40090
  40. 1700

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