← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 612 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  2. 2.What amount will ₹58900 grow to in 2 years at 20% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹4300 at 20% per year for 2 years (in ₹)?
  4. 4.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  5. 5.What amount will ₹22400 grow to in 2 years at 25% per year compound interest (in ₹)?
  6. 6.What amount will ₹14800 grow to in 1 year at 25% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹18100 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹6900 grow to in 1 year at 15% per year compound interest (in ₹)?
  10. 10.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹50100 at 20% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹2400 at 10% per year for 2 years (in ₹)?
  14. 14.What amount will ₹38500 grow to in 1 year at 8% per year compound interest (in ₹)?
  15. 15.What amount will ₹17600 grow to in 2 years at 25% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹6000 at 20% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹48000 at 15% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹33900 at 15% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹8400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  20. 20.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹40200 at 20% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
  25. 25.What amount will ₹57300 grow to in 1 year at 4% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹43600 at 5% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹53200 at 5% per year for 2 years, compounded every year (in ₹).
  29. 29.What is the difference between the compound interest and the simple interest on ₹8700 at 10% per year for 2 years (in ₹)?
  30. 30.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  31. 31.A town has 5600 people. The population grows by 15% every year. What will the population be after 2 years?
  32. 32.A town has 27900 people. The population grows by 5% every year. What will the population be after 1 year?
  33. 33.What is the difference between the compound interest and the simple interest on ₹55500 at 10% per year for 2 years (in ₹)?
  34. 34.What amount will ₹54200 grow to in 1 year at 15% per year compound interest (in ₹)?
  35. 35.A scooter is worth ₹34800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  36. 36.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹14000 at 5% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹15100 at 12% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 8334
  2. 84816
  3. 172
  4. 36501
  5. 35000
  6. 18500
  7. 336
  8. 724
  9. 7935
  10. 40768
  11. 7904
  12. 10020
  13. 24
  14. 41580
  15. 27500
  16. 2640
  17. 1080
  18. 5085
  19. 7581
  20. 31360
  21. 40656
  22. 84
  23. 17688
  24. 56
  25. 59592
  26. 540
  27. 109
  28. 5453
  29. 87
  30. 52992
  31. 7406
  32. 29295
  33. 555
  34. 62330
  35. 33408
  36. 60835
  37. 756
  38. 3264
  39. 1435
  40. 1812

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets