Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹30100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 2.Find the compound interest on ₹20700 at 5% per year for 1 year, compounded every year (in ₹).
- 3.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 4.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 5.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
- 6.A scooter is worth ₹25200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 7.Find the compound interest on ₹53800 at 10% per year for 2 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹17900 at 10% per year for 2 years, compounded every year (in ₹).
- 9.A town has 23300 people. The population grows by 8% every year. What will the population be after 1 year?
- 10.A town has 22500 people. The population grows by 4% every year. What will the population be after 2 years?
- 11.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
- 12.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹2700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
- 16.A town has 2000 people. The population grows by 5% every year. What will the population be after 1 year?
- 17.What amount will ₹16000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹59500 at 10% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 20.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 21.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹27000 at 25% per year for 1 year, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 26.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 27.A scooter is worth ₹43600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 28.Find the compound interest on ₹58900 at 4% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹49400 at 20% per year for 1 year, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹27900 at 10% per year for 2 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹12000 at 25% per year for 2 years (in ₹)?
- 34.A town has 46200 people. The population grows by 10% every year. What will the population be after 2 years?
- 35.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
- 36.What amount will ₹40100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
- 38.A scooter is worth ₹49000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 39.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
Answer key
- 24381
- 1035
- 37044
- 29478
- 43904
- 18207
- 11298
- 3759
- 25164
- 24336
- 2912
- 21632
- 128
- 2565
- 270
- 2100
- 17280
- 5950
- 32
- 46305
- 15525
- 100
- 6750
- 37
- 108
- 64827
- 24525
- 2356
- 9880
- 336
- 5859
- 1664
- 750
- 55902
- 816
- 43308
- 1107
- 43120
- 16881
- 16668
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets