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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 615 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A scooter is worth ₹30100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  2. 2.Find the compound interest on ₹20700 at 5% per year for 1 year, compounded every year (in ₹).
  3. 3.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  4. 4.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  5. 5.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
  6. 6.A scooter is worth ₹25200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.Find the compound interest on ₹53800 at 10% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹17900 at 10% per year for 2 years, compounded every year (in ₹).
  9. 9.A town has 23300 people. The population grows by 8% every year. What will the population be after 1 year?
  10. 10.A town has 22500 people. The population grows by 4% every year. What will the population be after 2 years?
  11. 11.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
  12. 12.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹2700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
  16. 16.A town has 2000 people. The population grows by 5% every year. What will the population be after 1 year?
  17. 17.What amount will ₹16000 grow to in 1 year at 8% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹59500 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
  20. 20.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹27000 at 25% per year for 1 year, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
  26. 26.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹43600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  28. 28.Find the compound interest on ₹58900 at 4% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹49400 at 20% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹27900 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹12000 at 25% per year for 2 years (in ₹)?
  34. 34.A town has 46200 people. The population grows by 10% every year. What will the population be after 2 years?
  35. 35.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
  36. 36.What amount will ₹40100 grow to in 1 year at 8% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹49000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  39. 39.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 24381
  2. 1035
  3. 37044
  4. 29478
  5. 43904
  6. 18207
  7. 11298
  8. 3759
  9. 25164
  10. 24336
  11. 2912
  12. 21632
  13. 128
  14. 2565
  15. 270
  16. 2100
  17. 17280
  18. 5950
  19. 32
  20. 46305
  21. 15525
  22. 100
  23. 6750
  24. 37
  25. 108
  26. 64827
  27. 24525
  28. 2356
  29. 9880
  30. 336
  31. 5859
  32. 1664
  33. 750
  34. 55902
  35. 816
  36. 43308
  37. 1107
  38. 43120
  39. 16881
  40. 16668

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